Let the consecutive multiples of 7 be 7x and 7(x+1).
7x + 7(x+1) = 126
7x + 7x + 7 = 126
14x + 7 + 126
14x = 126 - 7
14x = 119
x = 119/14
x = 8.5
For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.
They are 63 and 126
It is -7,-6,-5,-4!
88 / 4 = 22 = 4 + 5 + 6 + 7... so 4(4) + 4(5) + 4(6) + 4(7) = 16 + 20 + 24 + 28 = 88
The lowest common multiple of 7 and 9 is 63. The common multiples of 7 and 9 are therefore the infinite set of multiples of 63. Thus, the common multiples of 7 and 9 are 63, 126, 189, 252, 315, 378, 441, 504, 567, 630, 693, and so on.
The common multiples of 7, 14, and 21 are the infinite set of multiples of their least common multiple, which is 42. So the common multiplesof 7, 14, and 21 are 42, 84, 126, 168, and so on.Any multiple of 42.
91
All odd numbers are the sum of two consecutive numbers. Odd multiples of 7 less than 25 are 7 and 21.
18 times 7 = 126
7 x 18 = 126 126 is a common multiple of 7 and 18
They are: 2*3*3*7 = 126
91, 98, 105, 112
Any multiple of 126.
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
0, 7, 14, 21... Keep adding 7 at a time, until you reach or pass the number 126.
42, 84, 126 and so on.
63, 126, 189 and so on.
42, 84, 126