Assuming that the rate of acceleration is constant and 8 miles per second2 NOT 8 miles per second, as stated,
then v2 = u2 + 2as where
v = final velocity = 64 mph
u = initial velocity = 0 mph
a = acceleration = 8 miles/s2
s = distance travelled (in miles)
so s = (v2 - u2)/(2a) = 64*64/(2*8) = 256 miles.
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
In a second, light travels about 300,000 km., or 3x108 meters.
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
2 meters every second. bit pointless
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
Objects in free fall will be accelerating, so you need to know which second that you are interested in, and the acceleration from gravity (9.8 meters per sec2) The formula for distance is: d = v0*t + (1/2)*a*t2. Where v0 is the initial velocity, t is time, and a is acceleration.
96 feet per second
Acceleration is the rate of change of the velocity. Accelerating mean the object is increasing the velocity with time.
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
distance per time2 is acceleration, yes. Note however, it's per, not pre
In general, nowhere, because acceleration is the second derivative of distance with respect to time. However, in the special case of a constant acceleration, the acceleration will be twice the slope of the line, since distance = 0.5 * time squared.
Well, Speed is not the same thing as Acceleration. But to answer you question the best I can: the numerical value of speed can be higher than the numerical value of acceleration - for example, an object can have a speed of 10 feet per second while accelerating at 2 feet per second squared.
You would need to sample the velocity at at least two different points of time in order to determine how to velocity is changing. This is because velocity is the first order integral of acceleration, making acceleration the first order differential of velocity. Distance does not really enter into the equation as that is a second order factor, except that you can use distance traveled from one time to the next to estimate velocity
In a second, light travels about 300,000 km., or 3x108 meters.
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
It is accelerating at 1.2m/s per second.
To convert acceleration to velocity, you must integrate.Similarly, to convert velocity to distance, you must integrate a second time. This is why the distance covered by a projectile is a second order quadratic equation.