You have five numbers that add up to 115. What is the average value of those five numbers? Now, how do you choose five consecutive numbers that have that average value?
Add the five numbers together and then divide that number by 5
generally you would multiply a number by itself, but i have found out a marvelous trick, and it is pretty easy since I am only a child, but starting with 1, if you add three, you get four, the next square number. then you add five to get nine the next square number, then seven to get sixteen and so on. So in simpler terms you take one and add three to get the next square number, then add five, then seven counting by odd numbers. Here is an equation. the bold numbers are the square numbers and the Italic numbers are the progressing odd numbers.1+3= 4+5= 9+7=16and so on.
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
Just add all the numbers, then divide by the size of the set. For example, if you have a set of five numbers, add all of them, then divide the result by five.
The numbers are: (3 +square root of 153) and (3 -square root of 153)
The two square numbers that add up to 225 are 144+81 = 225
The two square numbers which add up to 13 are 9 (which is equal to 3 squared), and 4 (which is equal to 2 squared).
The numbers are: (-12+square root of 171) and (-12-square root of 171)
the answer is for example 9+16=25=square number
You can't find five odd numbers that add up to fifty; the sum of five odd numbers will always be odd.
The numbers are: 11+ square root of 415 and 11 - square root of 415
16 and 64
the two numbers in the circles add up to the number in the square box!
9 + 16 = 25
The numbers are: 12+square root of 304 and 12-square root of 304