I got no idea
31
When you subtract one square number from another and the result is 27, you can express this as ( a^2 - b^2 = 27 ), where ( a ) and ( b ) are integers. This can be factored into ( (a - b)(a + b) = 27 ). The pairs of factors of 27 are (1, 27), (3, 9), and their negative counterparts. Solving these pairs will yield possible values for ( a ) and ( b ).
Set up the equation: 3b-2=7. Solve for b: Subtract 2 from both sides: 3b=9. b=3.
I ask my 11 year old son. 2b + 18 = 4b Subtract 2b form each side: 18 = 2b Divide each side by 2: 9 = b which is the same as b = 9, but you knew that, didn't you?
To solve the equation ( a^2 - b^2 = 9 ), we can factor it as ( (a - b)(a + b) = 9 ). The pairs of factors of 9 are (1, 9) and (3, 3). By solving these pairs, we find that one possible solution is ( a = 5 ) and ( b = 4 ) (since ( 5^2 - 4^2 = 25 - 16 = 9 )). Thus, the two square numbers are 25 and 16.
The question is not clear
31
In order to answer, we must know what bequals.
When you subtract one square number from another and the result is 27, you can express this as ( a^2 - b^2 = 27 ), where ( a ) and ( b ) are integers. This can be factored into ( (a - b)(a + b) = 27 ). The pairs of factors of 27 are (1, 27), (3, 9), and their negative counterparts. Solving these pairs will yield possible values for ( a ) and ( b ).
Subtract the remainder which is left when the digital root is divided by 9.
Set up the equation: 3b-2=7. Solve for b: Subtract 2 from both sides: 3b=9. b=3.
I ask my 11 year old son. 2b + 18 = 4b Subtract 2b form each side: 18 = 2b Divide each side by 2: 9 = b which is the same as b = 9, but you knew that, didn't you?
-7
The two square numbers that subtract to 7 are 16 and 9. Specifically, (4^2 = 16) and (3^2 = 9), and when you subtract 9 from 16, you get 7: (16 - 9 = 7).
You can only add or subtract like terms. So, you subtract 9x from 2x, which gives you -7x. Then subtract -9 from 3 to get -6. And you are left with -7x -6.
15
9