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What is a "root"? A root is a value for which a given function equals zero. When that function is plotted on a graph, the roots are points where the function crosses the x-axis.

For a function, f(x), the roots are the values of x for which f(x)=0. For example, with the function f(x)=2-x, the only root would be x = 2, because that value produces f(x)=0.

Of course, it's easy to find the roots of a trivial problem like that one, but what about something crazy like this:

Steps to find roots of rational functions

  1. Set each factor in the numerator to equal zero.
  2. Solve that factor for x.
  3. Check the denominator factors to make sure you aren't dividing by zero!

Numerator Factors

Remember that a factor is something being multiplied or divided, such as (2x-3) in the above example. So, the two factors in the numerator are (2x-3) and (x+3). If either of those factors can be zero, then the whole function will be zero. It won't matter (well, there is an exception) what the rest of the function says, because you're multiplying by a term that equals zero.

So, the point is, figure out how to make the numerator zero and you've found your roots (also known as zeros, for obvious reasons!). In this example, we have two factors in the numerator, so either one can be zero. Let's set them both equal to zero and then solve for the x values:

2x - 3 = 0

2x = 3

x = 3/2

AND

x + 3 = 0

x = -3

So, x = 3/2 and x = -3 become our roots for this function. They're also the x-intercepts when plotted on a graph, because y will equal 0 when x is 3/2 or -3.

Denominator Factors

Just like with the numerator, there are two factors being multiplied in the denominators. They are x and x-2. Let's set them both equal to zero and solve them:

x = 0

AND

x - 2 = 0

x = 2

Those are not roots of this function. Look what happens when we plug in either 0 or 2 for x. We get a zero in the denominator, which means division by zero. That means the function does not exist at this point. In fact, x = 0 and x = 2 become our vertical asymptotes (zeros of the denominator). So, there is a vertical asymptote at x = 0 and x = 2 for the above function.

Here's a geometric view of what the above function looks like including BOTH x-intercepts and BOTH vertical asymptotes:

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Q: What do you mean by sum and product of the roots?
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Related questions

What is the sum and product of roots of a quadratic equation?

the sum is -b/a and the product is c/a


If the sum of the roots of x2 3x-5x0 is added to the product of the roots?

Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.


What is the relationship between the sum and product of the roots?

parallel


How do you get a sum and the product of the roots?

multiply by one if ur looking for the sum and divide by one if look ing for the product, easy


Whats the formula for sum and product of roots?

an + an = 2an; an x an = an + n


Does product and sum mean the same?

No - the product of numbers is the answer to a multiplication sum, while the sum of numbers is the answer to an addition sum.


What is the equation for The product of 5 and the sum of 8 and 2?

find the sum and product of the roots of 8×2+4×+5=0


What is the interior angles of a stop sign?

3x squared - 12x - 24 = 0, and -b/a = sum of the roots, and c/a = product of the roots


Are there two integers with a product of-12 and a sum of-3?

-9


What roots of the quadratic equation are equivalent to xx-x-12 equals 0?

-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12


Formula of quadratic equation if roots are given?

A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0


What does it mean to find the product of something?

Product means to multiply the operands. The product of 5 and 6 is 30. Sum means to add the operands. The sum of 5 and 6 is 11.