"5 C B" typically refers to "five-cornered box," a term often used in various contexts such as geometry or packaging. However, without specific context, its meaning can vary. In some cases, it might also be an acronym or abbreviation relevant to a particular field or subject. If you provide more context, I can help narrow down its meaning further.
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
To determine the relationship between a, b, and c given the equations ( a + b = 2 ), ( b + c = 5 ), and ( c + a = 9 ), we can solve these equations simultaneously. From the first equation, we can express ( a ) as ( a = 2 - b ). Substituting ( a ) into the third equation gives ( c + (2 - b) = 9 ), which simplifies to ( c - b = 7 ). Combining this with the second equation ( b + c = 5 ) allows us to solve for ( b ) and subsequently find ( a ) and ( c ). Ultimately, we find that ( a = -1 ), ( b = 3 ), and ( c = 2 ).
If any number B is subtracted from a number A to give C, then C+B =A If A - B = C then B+C = A Eg 7 - 2 = 5 Hence 2 + 5 = 7
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
There are infinitely many possible answers. They are all of the form {a, b, c, d and 25-(a+b+c+d+)} where a, b, c and d are numbers: positive or negative, rational, irrational or even complex.
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
It means that FOR CERTAIN OPERATIONS, you can start at the left or at the right, and get the same results. In the case of addition of real numbers, in symbols, you have:(a + b) + c = a + (b + c) An example with specific numbers: (20 + 10) + 5 = 20 + (10 + 5) Similar for multiplication of real numbers. Parentheses mean that you should do the operation inside the parentheses first.
C, D ,B,A,A,C,B,C,C,B,C,D,A,D,B,B,D,B,A,C
To determine the relationship between a, b, and c given the equations ( a + b = 2 ), ( b + c = 5 ), and ( c + a = 9 ), we can solve these equations simultaneously. From the first equation, we can express ( a ) as ( a = 2 - b ). Substituting ( a ) into the third equation gives ( c + (2 - b) = 9 ), which simplifies to ( c - b = 7 ). Combining this with the second equation ( b + c = 5 ) allows us to solve for ( b ) and subsequently find ( a ) and ( c ). Ultimately, we find that ( a = -1 ), ( b = 3 ), and ( c = 2 ).
You need to add all the values shown on the histogram and then divide that sum by the number of values (samples). Example: There are 5 values: A, B, C, D, E. Mean value is: (A+B+C+D+E) / 5
You haven't provided any choices for the "which of the following" part of your question. Such questions are best avoided here. However, assuming a, b and c are all natural numbers, all of the following are true for a<b AND b+c=10: a=1, b=2, c=8 a=1, b=3, c=7 a=1, b=4, c=6 a=1, b=5, c=5 a=1, b=6, c=4 a=1, b=7, c=3 a=1, b=8, c=2 a=1, b=9, c=1 a=2, b=3, c=7 a=2, b=4, c=6 a=2, b=5, c=5 a=2, b=6, c=4 a=2, b=7, c=3 a=2, b=8, c=2 a=2, b=9, c=1 a=3, b=4, c=6 a=3, b=5, c=5 a=3, b=6, c=4 a=3, b=7, c=3 a=3, b=8, c=2 a=3, b=9, c=1 a=4, b=5, c=5 a=4, b=6, c=4 a=4, b=7, c=3 a=4, b=8, c=2 a=4, b=9, c=1 a=5, b=6, c=4 a=5, b=7, c=3 a=5, b=8, c=2 a=5, b=9, c=1 a=6, b=7, c=3 a=6, b=8, c=2 a=6, b=9, c=1 a=7, b=8, c=2 a=7, b=9, c=1 a=8, b=9, c=1
The transitive property states that if A equals B and B equals C, then A equals C. For example, if a = 5 and b = 5, then we can conclude that a = b. If b = c (where c is also 5), it follows that a = c, demonstrating the transitive relationship among the three values.
Oh, and I mean A+B+C=BB
If any number B is subtracted from a number A to give C, then C+B =A If A - B = C then B+C = A Eg 7 - 2 = 5 Hence 2 + 5 = 7