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There is a 95% probability that the true population proportion lies within the confidence interval.

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Q: What does a 95 percent confidence interval tell you about the population proportion?
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When the sample size and sample standard deviation remain the same a 99 percent confidence interval for a population mean will be narrower than the 95 percent confidence interval for the mean?

Never!


Is a 95 percent confidence interval for a mean wider than a 99 percent confidence interval?

No, it is not. A 99% confidence interval would be wider. Best regards, NS


99 percent confidence interval Population mean 24.4 to 38.0 find the mean sample?

if the confidence interval is 24.4 to 38.0 than the average is the exact middle: 31.2, and the margin of error is 6.8


What would happen to the width of the confidence interval if the level of confidence is lowered from 95 percent to 90 percent?

decrease


What is the Z value for 91 percent confidence interval estimation?

The Z-value for a one-sided 91% confidence interval is 1.34


What is confidence intervals in statistics?

The Confidence Interval is a particular type of measurement that estimates a population's parameter. Usually, a confidence interval correlates with a percentage. The certain percentage represents how many of the same type of sample will include the true mean. Therefore, we would be a certain percent confident that the interval contains the true mean.


Difference between 95 percent and 99 percent confidence interval?

4.04%


When determining the 95 percent confidence interval for a population mean with known sigma the value of the critical value of z is equal to?

1.96


Compute the population mean margin of error for a 90 percent confidence interval when sigma is 4 and the sample size is 36?

1.0966


What is z value for 90 percent confidence interval?

For a two-tailed interval, they are -1.645 to 1.645


How should I construct a confidence interval for the population proportion p with n equals 144 and x equals 82 with a 90 percent confidence level?

The confidence interval will be Pi+-z*spz5%= 1.6449Pi = x/nSp = Sqrt(Pi(1-Pi)/n)Pi ~= 0.5694Sp = Sqrt(.5694*0.4306/144) ~= 0.0413Pi - 0.0679 < p < Pi + 0.06790.5016 < p < 0.6373You can do this on your TI-83/84 with 1-PropZInt (Stat->Tests->A)


Uwant totestcreatedWeb site so you have 250 people access it. Of the peps accessing the site 75 of them exp. computer crashes. Construct a 95 percent confidence interval for the proportion of crashes?

Estimated p = 75 / 250 = 0.3 Variance of proportion = p*(1-p)/n = 0.3(0.7)/250 =0.00084 S.D. of p is sqrt[0.00084] = 0.029 Confidence interval: phat-zval*sd = 0.3 - (1.96)(0.028983) phat-zval*sd = 0.3 + (1.96)(0.028983) Confidence interval is ( 0.2432 , 0.3568 )