a parallelogram with opposite equal acute angles, opposite equal obtuse angles, and four equal sides.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
A rhombus is a rectangle when one of its angles is a right angle.(Actually, a rectangle has 4 right angles. But you only have to prove that yourrhombus has one of them for sure, because then it turns out that it must havefour of them.)(Also, before you get all upset because a rhombus with right angles is actuallya square, we're aware of that too. Technically, a square is a special kind ofparallelogram, rhombus and rectangle too.)
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
A rhombus may be a square or just a rhombus (a rhombus is merely called a rhombus when there are no 90 degree angles).
Rhombus Not a SquareIn a square, the sides are perpendicular. In a rhombus, they aren't. A rhombus is never a square.
A rhombus has two sets of parrallell sides. If it has two set of parrellell sides, it is a rhombus.
Yes, it is one of the ways to prove a figure is a rhombus. If adjacent sides are congruent, then the figure is a rhombus.
A square is a rhombus with a right angle (90 degrees) at one corner.Note:That means that all four angles will be right angles, but in order to prove thatyour rhombus is a square, it's only necessary to prove that one angle is.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
You would have a difficult time finding a formula to prove that statement, for two main reasons: 1). The statement is false. A triangle is never a rhombus. 2). Formulas can describe things, but they can't 'prove' things.
I am a rhombus. I don't need to prove that my opposite sides are parallel. If I'm a quadrilateral with four sides that are the same length, then I am definitely a rhombus.
A rhombus is a rectangle when one of its angles is a right angle.(Actually, a rectangle has 4 right angles. But you only have to prove that yourrhombus has one of them for sure, because then it turns out that it must havefour of them.)(Also, before you get all upset because a rhombus with right angles is actuallya square, we're aware of that too. Technically, a square is a special kind ofparallelogram, rhombus and rectangle too.)
Since the diagonals of a rhombus are perpendicular between them, then in one forth part of the rhombus they form a right triangle where hypotenuse is the side of the rhombus, the base and the height are one half part of its diagonals. Let's take a look at this right triangle.The base and the height lengths could be congruent if and only if the angles opposite to them have a measure of 45⁰, which is impossible to a rhombus because these angles have different measures as they are one half of the two adjacent angles of the rhombus (the diagonals of a rhombus bisect the vertex angles from where they are drawn), which also have different measures (their sum is 180⁰ ).Therefore, the diagonals of a rhombus are not congruent as their one half are not (the diagonals of a rhombus bisect each other).
A rhombus. A rhombus. A rhombus. A rhombus.
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
A rhombus may be a square or just a rhombus (a rhombus is merely called a rhombus when there are no 90 degree angles).
It's fairly trivial to prove that the angles formed by the angle bisectors of any rhombus (including squares) are right angles.