To specify a vector, you need a length (or magnitude), and a direction.
You need to know that the cross product of two vectors is a vector perpendicular to both vectors. It is defined only in 3 space. The formula to find the cross product of vector a (vector a=[a1,a2,a3]) and vector b (vector b=[b1,b2,b3]) is: vector a x vector b = [a2b3-a3b2,a3b1-a1b3,a1b2-a2b1]
Yes, a vector can be represented in terms of a unit vector which is in the same direction as the vector. it will be the unit vector in the direction of the vector times the magnitude of the vector.
The zero vector is both parallel and perpendicular to any other vector. V.0 = 0 means zero vector is perpendicular to V and Vx0 = 0 means zero vector is parallel to V.
Resultant vector or effective vector
You need the magnitude and the distance for defining the vector quantity
"North" is a valid direction, but for a vector, you would also need a magnitude.
"North" is a valid direction, but for a vector, you would also need a magnitude.
To specify a vector, you need a length (or magnitude), and a direction.
due to space vector modulation we can eliminate the lower order harmonics
You need to know that the cross product of two vectors is a vector perpendicular to both vectors. It is defined only in 3 space. The formula to find the cross product of vector a (vector a=[a1,a2,a3]) and vector b (vector b=[b1,b2,b3]) is: vector a x vector b = [a2b3-a3b2,a3b1-a1b3,a1b2-a2b1]
In the case of the dot product, you would need to find a vector which, multiplied by another vector, gives a certain real number. This vector is not uniquely defined; several different vectors could be used to give the same result, even if the other vector is specified. For the other two common multiplications defined for vector, the inverse of multiplication, i.e. the division, can be clearly defined.
You don't need to prove much - just look at the definition of a vector. A vector includes a magnitude (in this case the force), and a direction. Since weight (or "the force of gravity") is directed to a certain direction, namely downward, you can consider it a vector.You don't need to prove much - just look at the definition of a vector. A vector includes a magnitude (in this case the force), and a direction. Since weight (or "the force of gravity") is directed to a certain direction, namely downward, you can consider it a vector.You don't need to prove much - just look at the definition of a vector. A vector includes a magnitude (in this case the force), and a direction. Since weight (or "the force of gravity") is directed to a certain direction, namely downward, you can consider it a vector.You don't need to prove much - just look at the definition of a vector. A vector includes a magnitude (in this case the force), and a direction. Since weight (or "the force of gravity") is directed to a certain direction, namely downward, you can consider it a vector.
i also need the answer can anybody tell me too
Yes, a vector can be represented in terms of a unit vector which is in the same direction as the vector. it will be the unit vector in the direction of the vector times the magnitude of the vector.
In physics, "velocity" is defined as a vector. That means that you either need to know:The magnitude of the velocity and the direction, orThe vector's components. For example, in two dimensions, you would need the x-component and the y-component.
No. In order for the magnitude of a vector to be zero, the magnitude of all of its components will need to be zero.This answer ignores velocity and considers only the various N-axis projections of a vector. This is because direction is moot if magnitude is zero.