change in velocity
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
Magnitude of acceleration (but conveys no informationregarding acceleration's direction).
The slope of the speed/time graph is the magnitude of acceleration. (It's very difficult to draw a graph of velocity, unless the direction is constant.)
Motion at a constant speed - no acceleration or deceleration.
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
its the velocity
The slope of a velocity-time graph represents acceleration.
Nothing in particular. It certainly does not represent acceleration.
The slope of a velocity-time graph represents acceleration.
The slope of a velocity-time graph represents acceleration.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
Magnitude of acceleration (but conveys no informationregarding acceleration's direction).
Magnitude of acceleration (but conveys no informationregarding acceleration's direction).
The rate of Change in acceleration.
The slope of the speed/time graph is the magnitude of acceleration. (It's very difficult to draw a graph of velocity, unless the direction is constant.)
deceleration or negative
magnitude of acceleration at every point on the graph