The equation has infinitely many solutions.

16 = 16 is an identity, not an equation. An identity does not have solutions.

An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3

One solution: x = -4

-2

There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.

There is only one solution to that equation. It's . . . . . x = -16

It will have two solutions because its a quadratic equation: x = -8.472135955 or x = 0.472135955

X = 8That equation has exactly one solution.The solution is:x = 8

An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.

6

Since the highest power of 'x' in the equation is '1', there's one solution.

The quadratic equation will have two solutions.

There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)

It has one double solution.

x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.

Quadratic equations like this one usually have two solution. Sometimes they have one (so-called "double") solution. If you solve it, you'll know for sure.

The equation has no solution. Since if you combine like terms, you get 0=-10 which isn't true, there are no solutions to the equation.

There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.

One solution.

Because 8 does not = 7, there is no solution. You write No Sol. Alternatively if you simplify an equation to x = x, that would be All Solutions (any number substituted for x satisfies the equation) * * * * * Wrong! 8x = 7x DOES have a solution and that is x = 0

0x2 + 1x - 7 = 0

That looks like a linear equation (no quadratic or higher terms), so you can expect it to have a single solution. However, actually solving the equation is not difficult; do it, to confirm this.

Without an equality sign the given expression can't be considered to be an equation but if it equals 0 then using the quadratic equation formula will give its solutions.

y = -2.5 is a equation. And solution to the equation is finding the value of the variable. If we see the equation y is already equal to -2.5 which is the solution to the equation.

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