Nothing in particular. It certainly does not represent acceleration.
The area under a graph of force against distance (or extension, if it's a spring) represents the work done by that force. Since it sounds like you're talking about a spring, you should know that the area would represent the work done to stretch the spring that distance, and also represents the amount of elastic potential energy contained by the spring.
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Yuo cannot include a graphical illustration here. Take a look at the Wikipedia, under "exponential function" and "logistic function". Basically, the exponential function increases faster and faster over time. The logistics function initially increases similarly to an exponential function, but then eventually flattens out, tending toward a horizontal asymptote.
The discriminant is the expression under the square root of the quadratic formula.For a quadratic equation: f(x) = ax2 + bx + c = 0, can be solved by the quadratic formula:x = (-b +- sqrt(b2 - 4ac)) / (2a).So if you graph y = f(x) = ax2 + bx + c, then the values of x that solve [ f(x)=0 ] will yield y = 0. The discriminant (b2 - 4ac) will tell you something about the graph.(b2 - 4ac) > 0 : The square root will be a real number and the root of the equation will be two distinct real numbers, so the graph will cross the x-axis at two different points.(b2 - 4ac) = 0 : The square root will be zero and the roots of the equation will be a real number double root, so the graph will touch the x-axis at only one points.(b2 - 4ac) < 0 : The square root will be imaginary, and the roots of the equation will be two complex numbers, so the graph will not touch the x-axis.So by looking at the graph, you can tell if the discriminant is positive, negative, or zero.
The integral function of calculus is the method for determining the area under a curve. The limiting chord process is the "simple" math understanding required to learn the "complex" function of "integration". BTW: the derivative function is a "cousin" of the integral function which is used to determine the slope of curve at a given point.
At least two things regarding the motion can be interpreted from the graph of speed versus time.The slope of the graph represents the acceleration of the thing being charted.And the net area under the graph represents the position of the thing being charted.Each of these graphed as they change with time, on the same time scale as the original graph or some other one if more convenient.
The area of a position-time graph does not have a meaning. However, the area under a velocity-time graph is the displacement. Refer to the related link below for an illustration.
The distance travelled over the time period represented by the area under the v-t graph between the end points.
The position at time t (and therefore the height of the p-t graph) will be the area under the v-t curve between time 0 and t.
postion is the area under the slope
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
Position-Time GraphYou can graph motion on a position vs time graph. On a position vs time graph, position is on the y-axis and time is on the x-axis. If the velocity is constant, the graph will be a straight line and the slope is average velocity. If the motion is accelerating, the graph will be a curved line.Velocity-Time GraphYou can also graph motion on a Velocity-Time graph. On a velocity vs time graph, velocity is on the y-axis, time is on the x-axis. If the graph is a straight line, velocity is constant and the slope is average acceleration. Also, on a velocity vs time graph, the area under the line is displacement.Refer to the related link for illustrations of the different graphs of motion and their meanings.
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
The area under a graph of force against distance (or extension, if it's a spring) represents the work done by that force. Since it sounds like you're talking about a spring, you should know that the area would represent the work done to stretch the spring that distance, and also represents the amount of elastic potential energy contained by the spring.
The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.