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The area under the velocity time graph is related to the distance travelled in the direction in which the velocity is measured but not the orthogonal direction.
So for example if I bounce a ball straight up and down, but measure its velocity only in the horizontal direction, then the v-t graph will be at zero at all times indicating no distance has been travelled. This is true in the horizontal direction but not in the vertical direction. This happens because velocity is a vector whereas distance travelled is a scalar.
Also, the area under a velocity time graph is the distance travelled - PROVIDED the graph remains at, or above, the time axis at all times; that is, the velocity remains positive at all times.
If the velocity becomes negative for part of the time then the absolute value of the area above the V-T graph is the relevant bit.
Wiki User
∙ 13y ago
Wiki User
∙ 13y agoThe velocity of an object (v) at any particular instant is the distance covered by that object (s) divided by the time interval (t) taken to cover the distance. When the velocity is changing, the instantaneous velocity is the distance covered in a very, very short time divided by the very, very short period taken to cover it.
In differential calculus, this would be denoted by v = ds/dt
By definition, then, s is the integral of v with respect to time. Graphically, this is the area under the velocity-time graph.
Wiki User
∙ 12y agoVelocity is calculated as displacement divided by time. V = d/t. When this figure is multiplied by time, the time in this formula is 'cancelled out', leaving only the displacement. Consider the equation below:
d/t x t/1 = d
There is a time figure on the top of one fraction, and the bottom of the other. These cancel each other out, leaving the displacement.
In calculating the area under the curve, the velocity is multiplied by the time figure, giving a displacement figure.
Wiki User
∙ 14y agoIt is the displacement under a certain time deltaT.
Wiki User
∙ 11y agoThe area under a speed/time graph, between two time points,
indicates the total distance traveled during that time.
Wiki User
∙ 11y agoThe displacement on a velocity-time graph is the area beneath the line.
Wiki User
∙ 13y agoDistance
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Give me another term for the area under a velocity-time graph?
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)
Find position given velocity vs time graph?
postion is the area under the slope
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Velocity is the slope of the displacement vs time graph?
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
What are the advantages of velocity time graph?
Normally a position-time graph is actually a distance-time graph where the distance of an object is measured from a fixed point called the origin. The slope (gradient) of the graph is the radial velocity - or the component of the velocity in the radial direction - of the object. That is, the component of the object's velocity in the direction towards or away from the origin. Such a graph cannot be used to measure the component of the velocity at right angles to the radial direction. In particular, an object going around in a circle would appear t have no velocity since its distance from the origin remains constant.
What does the area under an acceleration time graph show?
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
What equals the displacement on a velocity-time graph?
Displacement is the area under the v-t graph.
What does the area under the acceleration-time graph represent?
its the velocity
What is the area under the un uniform acceleration time graph?
Velocity.
Give me another term for the area under a velocity-time graph?
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)
What do you measure by finding area under the velocity time graph?
distance travelled
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
What is the area of a position time graph?
The area of a position-time graph does not have a meaning. However, the area under a velocity-time graph is the displacement. Refer to the related link below for an illustration.
The area under a velocity-time graph represents?
The distance travelled over the time period represented by the area under the v-t graph between the end points.
Area under the velocity versus time graph?
Area under velocity versus time graph(between two given instances of time i.e. two points on time axis) gives the displacement of the body( whose graph was plotted) between those two instances i.e. in that time interval. Area under velocity time graph can be found from definite integration if the graph is a curve. Note: Area under velocity versus time graph gives displacement not distance covered by body. Note: Area enclosed between the plotted curve and time axis is taken. For convenience time should be taken in the x-axis.
Can a position time graph be created from a velocity time graph?
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
Find position given velocity vs time graph?
postion is the area under the slope
