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Q: How do you write The quantity p minus five eighths times the quantity one fourth plus p?

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(p-5•8•4+p)

The equation is as follows: p - 5/8 (1/4 + p). This equation expands to (1/4)p + p^2 - 5/32 - (5/8)p, which simplifies to p^2 - (3/8)p - 5/32. Now either solve for p using the quadratic formula or solve by factoring.

(9 - y)(a + 5)

1/4 plus 1/4 times 7/8 is equal to 0.46875

It is: 1/4 times 6/8 = 3/16 in its lowest terms

1/4 x 5/8 = 5/32

The algebraic expression is 4q-3

13

68.3

Look in your text book. I am sure they have an example, or a formula that you can put the numbers into and get an answer. 407

-9(y-9) = -9y+81

(9 - y)(a + 5)

8(d-3)

4

It could be: -3/8+4x-9z as an algebraic expression

-68 I think

85/8 x 9/4 = 765/32 = 23 and 29/32

3 5/8 x 3 1/4 = 9 5/32

Thirty eighths. Or three and six eighths.

It is the same as: -2q-3 as an algebraic expression

seven-eighths

9/64

20/64=5/17

15/64

9/7 x 1/4 = 9/28 or nine twenty-eighths. Expressed as a decimal, this is equal to 0.32142857 recurring (that is, 0.32142857142857...)