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Q: What four consecutive integers whose sum is 102?

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The integers are 99, 100 and 101. There is also a set of consecutive even integers whose sum is 300. That set is 98, 100 and 102.

101 and 102

101 and 102

101+102=203

101 and 102

The numbers are 101 and 102.

They are: 101+102 = 203

101 and 102

The average of the three integers is going to be -306/3 = -102. Therefore, taking one even integer from either side, -306 = (-100) + (-102) + (-104)

They are (33, 34, 35).

306/3 = 102 so the three numbers are 101, 102 and 103.

102 = 32 + 34 + 36

The largest integer is 103 because 101+102+103 = 306

101 + 102 = 203. (Hint: solve the equation n + n+1 = 203.)

There are no two consecutive numbers that add or multiply to 102.

24, 25, 26, 27 (next to each other and add up to 102)

Yes: 1 and 0 are consecutive.

the sum of three consective even integers is negative 300

are integers that follow in sequence, each number being 1 more than the previous number, represented by n, n +1, n + 2, n + 3, ..., where n is any integer.* Integers are the so-called whole numbers: or the counting numbers, both positive and negative, and the number zero. Consecutive integers are any two or more integers that are in sequence. 1, 2 6, 7, 8, 9 -4, -3, -2 101, 102, 103, 104, 105, 106A consecutive integer is an integer that comes right before or after another integer.Example5,65 and 6 are consecutive integers.

x + x+1 = 203 2x+1 = 203 2x = 202 x = 101 x+1 = 102

Simply consider what ARE the sums of four consecutive non-negative integers: 0+1+2+3 = 61+2+3+4 = 102+3+4+5 = 143+4+5+6 = 18.... You can see that it's any number of the form: 6 plus a (non-negative integer) multiple of 4.A more mathematical proof is to consider an arbitrary starting number n, then: n+(n+1)+(n+2)+(n+3) = 4*n + 6 (which is the same as concluded above).

No. 102 is not evenly divisible by four.

One example of such a sum involving positive integers is: 204/2 = 102

there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.

-9 and +9 are between the two square roots of 102.