1/24 = 1/16
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
3/8
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg
1/2 (50%) of them.
0.62 and a half as a fraction is 5/8.
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
1 / 26 = 1 / 64.
Fraction remaining = 0.5^n where n = # of half lives that have elapsed60 yrs x 1 half life/12 yrs = 5 half lives have elapsed Fraction remaining = 0.5^5 = 0.03125 mass remaining = 0.03125 x 80.0 g = 2.5 g remaining
12.5% is remaining.
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
91.16% of the daughter product has formed after 3.5 half lives.
the half-life of chlorine 36 is 400,000 years. 200,000 years is 1/2 of a half life. in general, the formula to calculate the fraction of remaining amount is 1/2^n, where n represents the number of half-lives that have passed. in this case, n=1/2, or 0.5, therefore the remaining fraction is 1/2^0.5. Use your calculator and you will find that this is 0.707, or about 71% of the original amount. hope this helps
The fraction that remains is 1/8.
An eighth remains.
3/8
Iodine 131 is radioactive and has a half life of about 8 days. After 32 days there would be approximately 5 milligrams remaining
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg