To find the frequency corresponding to an absorption line at 502 nm, you can use the formula ( f = \frac{c}{\lambda} ), where ( c ) is the speed of light (approximately ( 3 \times 10^8 ) m/s) and ( \lambda ) is the wavelength in meters. First, convert 502 nm to meters: ( 502 , \text{nm} = 502 \times 10^{-9} , \text{m} ). Then, substituting the values gives ( f = \frac{3 \times 10^8 , \text{m/s}}{502 \times 10^{-9} , \text{m}} \approx 5.96 \times 10^{14} , \text{Hz} ).
3.77x10^-19 J
The transition energy corresponding to an absorption line at 502nm can be calculated using the formula E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, we get E = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (502 x 10^-9 m) ≈ 3.96 x 10^-19 J.
3.96 10-19 j
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20% of 502 = 20% * 502 = 0.2 * 502 = 100.4
The factors of 502 are: 1, 2, 251, 502.
12% of 502 = 502*12/100 = 60.24
502 = DII
502 is a Composite Number
Roman numeral 502 is represented as "DII" in Roman numerals.