Q: What happens if you add or subtract a value to both sides of an inequality?

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When you divide both sides by a negative value

No. Only when you divide by a negative.

You solve an inequality the same way you solve an equality. You add and subtract, multiply and divide, both sides by the same value in order to isolate one of the variables. The only extra thing you need to remember is that if you multiply or divide by a negative number, you must reverse the order of the inequality, i.e. less than or equal becomes greater than or equal.

When a quantity is subtracted or added from both sides of an inequality, the true difference in value is varied thereby changing the direction of the inequality, but when rather than subtracted or added it is multiplied or divided, it preserves the true difference in value thereby facing the same direction as the initial inequality.

Can you provide me with an inequality problem that the value is the same?

It is an equation used to anwer an absolute value inequality.

a solution of inequality

6 + 2x = x - 6 Subtract x from both sides: 6 + x = -6 Subtract 6 from both sides: x = -12

(X+6)/4 >= 2 First, remove the fraction on the left side by multiplying both sides by four X+6 >= 8 Subtract 6 from both sides to get your X value X >= 2

42

The range is the distance from the smallest value to the largest value. This is equivalent to the largest value MINUS the smallest value. Therefore you subtract.

Inequality

Obviously, a=3 To show... Simultaneously subtract the smaller variable on the right side (7a) from both sides and the lesser constant on the left side (-9) from both sides (subtracting a negative means to add a positive), or in other words... Subtract 7a from and add 9 to both sides to instantly force the value of 'a'... (1)a = 3 There, you have your answer... a=3

y = -32 6y + 22 = 4y - 42 subtract -4y from both sides 2y + 22 = -42 subtract 22 from both sides 2y = -64 Divide both sides by 2 to get y by itself y= -32

Since it is an inequality, there is no way to solve for x. It equals all real numbers.

Yes, but only when the inequality is not a strict inequality: thatis to say it is a "less than or equal to" or "more than or equal to" inequality. In such cases, the solution to the "or equal to" aspect will satisfy the corresponding inequality.

You need to solve for a by getting it by itself. You do this by performing the same operation on both sides of the equation 3a + 2 = a -6 subtract 2 from both sides: 3a = a -8 subtract a from both sides: 2a = -8 divide both sides by 2: a = -4

Divide both sides by 9: 9x > 27 → x > 3

When the value indicated by the circle is a valid value for the inequality.

8x + 7 = 55 Subtract 7 from both sides: 8x = 48 Divide both sides by 8: x = 6

8p = 3p + 25 Subtract 3p from both sides: 5p = 25 Divide both sides by 5: p = 5

Understanding place value helps me to subtract across zeros by putting a \ on it

The equation y = 7x + 10 can be solved when we know that y = 3. Using basically algebra, the value of x can be determined, which is -1. Simply subtract 10 from both sides of the equation and then divide both sides by 7.

It means that the inequality is less than the value of the dashed line and is not equal to it.

I think you have entered the inequality wrong. You have: 4j - 7 > 4j - 7 but that is saying that something is greater than itself as both sides of the greater than sign are the same expression.

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