The wavelength is halved.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
since v=f(lambda), where v is the speed in metres per second, f is the frequency in hertz and lambda the wavelength in metres , for this question, v= 440 x 1.5=660m/s
Its frequency would be higher. Imagine a guitar. When you put your finger higher up the fretboard, you shorten the string essentially. This has the effect of making the note higher
v = f h, h = lambda = wavelength. f = frequency in Hz v = velocity therefore, v = 1.5 * 440 (the units of v in this case are meters per second).
There is no such formula.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
The wavelength gets shorter.
Wavelength = speed/frequency = 350/640 = 54.7 centimeters (rounded)
it will moe faster
This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds. The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.
v=f*wavelength v=2*.5 v=1 m/s
speed = frequency × wave_length → frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
Question is to be corrected as to find the velocity of the sound waves Formula for velocity of the wave = frequency x wavelength Given frequency = 262 Hz and wavelength = 1.3 m So velocity = 262 x 1.3 = 340.6 m/s
The frequency of a pendulum is inversely proportional to the square root of its length. If you want to increase the frequency of a pendulum by a factor of 10, you make it 99% shorter.
Frequence of a wave is how often a string oscillates on a specific point between crests. So if the speed of the string is lowered, the crests of the wave will pass the point less often, causing lower frequency
Wavelength = velocity of sound in the medium / frequency Here velocity is not given. Let it be 330 m/s So required wavelength = 330/440 = 3/4 = 0.75 m
"Pressure" is not what causes strings to produce sound. It's "tension" which does that. Adjusting the tuners either increases or decreases the tension, thus altering the audible pitch. Bending the strings also increases the tension. The sound is due to the vibration of the strings. Greater tension causes a shorter, higher frequency wavelength or amplitude which produces a higher pitch. Lesser tension causes a longer, lower frequency wavelength which produces a lower pitch. Depressing the strings onto the fingerboard effectively shortens the length of the string. The more a string is shortened, the shorter its vibrational wavelength and the higher its frequency will become. The location along the fingerboard at which the string is depressed serves the same function as does the nut when a open string is sounded.