The answer depends on whether they are the foci of an ellipse or a hyperbola.
-- If they're the foci of a single optical system, then the result can't be stated in general.It depends on the curvatures and relative position of the lenses.-- If they're both the foci of the same ellipse, then the ellipse becomes more eccentric.That is, more squashed and less circular.-- If they're the foci of two parabolas, then there's no relationship between them, andnothing in particular depends on the distance between them.The answer depends on whether they are the foci of an ellipse or a hyperbola.
-- the eccentricity or -- the distance between the foci or -- the ratio of the major and minor axes
Foci, (the plural of focus), are a pair of points used in determining conic sections. They always fall on the major axis of symmetry of a conic. For example, in a circle, there is only one focus, the centerpoint. Every distance from the focus to any other point on the circle will be the same. In a parabola, the distance from any point of the parabola to the focus equals the distance from the centerpoint to the directrix. In a hyperbola, the difference of the distances between a point on the hyperbola and the focus points will be constant, and in an ellipse, the sum of the distances from any point on the ellipse to one of the foci is constant.
A half of a hyperbola is defined as the locus of points such that the distance of the point from one fixed point (a focus) and its distance from a fixed line (the directrix) is a constant that is greater than 1 (the eccentricity). By symmetry, a hyperbola has two foci and two directrices.
The standard equation for an ellipse centered at the origin is [x2/a2] + [y2/b2] = 1 We also have the relationship, b2 = a2 - c2 where c is the distance of the foci from the centre and a & b are the half lengths of the major and minor axes respectively. When the length of the minor axis equals the distance between the two foci then 2b = 2c : b = c. Thus, a2 =b2 + c2 = 2b2 One of the formulae for the eccentricity of an ellipse is, e = √[(a2 - b2)/a2] Thus, e = √[(2b2 - b2) / 2b2] = √½ = 1/√2.
As the distance between foci increases the eccentricity increases, or the reverse relationship.
-- If they're the foci of a single optical system, then the result can't be stated in general.It depends on the curvatures and relative position of the lenses.-- If they're both the foci of the same ellipse, then the ellipse becomes more eccentric.That is, more squashed and less circular.-- If they're the foci of two parabolas, then there's no relationship between them, andnothing in particular depends on the distance between them.The answer depends on whether they are the foci of an ellipse or a hyperbola.
eccentricity = distance between foci ________________ length of major axis
the eccentricity will increase.
-- the eccentricity or -- the distance between the foci or -- the ratio of the major and minor axes
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The eccentricity of an ellipse is a number related to how "egg-shaped" it is ... the difference between the distance through the fat part and the distance through the skinny part. That's also related to the distance between the 'foci' (focuses) of the ellipse. The farther apart the foci are, the higher the eccentricity is, and the flatter the ellipse is. Comets have very eccentric orbits. When the two foci are at the same point, the eccentricity is zero, all of the diameters of the ellipse have the same length, and the ellipse is a circle. All of the planets have orbits with small eccentricities.
the foci (2 focal points) and the distance between the vertices.
Most orbits are elliptical; all NATURAL orbits are. There are two foci, or focuses, to an ellipse. The distance between the foci determines how eccentric, or non-circular, they are. If the two foci are in the same place, then the ellipse becomes a circle. So a circular orbit would have only one focus.