-27x-3
.3 to the third power is .3x.3x.3 which is .027
3x^0 = 3(x^0) = 3 (3x)^0 = 1
4
3
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
4x to the 3rd power -4x to the 2nd power -43 when x=3
The integral of 3x is ln(3)*3x. Take the natural log of the base and multiply it by the base raised to the power.
It is -21x + 7
No, 9x - 3x is not 6, nor is it 6x. There is no simple one-term answer. The best that can be done is that it is 3x*(3x - 1).
3x^2 - 27 = = 3(x^2 - 9) = 3(x^2 - 3^2) = 3(x - 3)(x + 3)
it is no power if it was a power it would have a small 3 at the top of the right side of the x..
3x^4 - 12 = 3(x^4 - 4) = 3(x² + 2)(x² - 2)