It's the equation of a straight-line graph. Every point on the line is
a solution of the equation. There are an infinite number of them.
Wiki User
∙ 13y agoIt does nothing! 4x + 6y = 24 7x + 6y = 9 Subtracting the first equation from the second gives: 3x = - 15 so that x = -5 Substituting the value of x in the first equation gives -20 + 6y = 24 so that 6y = 44 and so y = 22/3 or 71/3
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
Two ways to see this: 6y=8-9+6y 6y=6y-1 No answer here 6y= 8-(9+6y) 6y+(9+6y)=8 12y+9=8 12y=-1 y= -(1/12) or -0.08333...
Subtract 7x from each side: 8 = -9 Not possible, game over.
8x-2 = -9+7x8x-7x = -9+2x=-7
It does nothing! 4x + 6y = 24 7x + 6y = 9 Subtracting the first equation from the second gives: 3x = - 15 so that x = -5 Substituting the value of x in the first equation gives -20 + 6y = 24 so that 6y = 44 and so y = 22/3 or 71/3
The variables in the given expression are x and y
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2
Two ways to see this: 6y=8-9+6y 6y=6y-1 No answer here 6y= 8-(9+6y) 6y+(9+6y)=8 12y+9=8 12y=-1 y= -(1/12) or -0.08333...
Subtract 7x from each side: 8 = -9 Not possible, game over.
8x-2 = -9+7x8x-7x = -9+2x=-7
7y-8 = 6y+1 7y-6y = 1+8 y = 9
7x + 9 = 51 7x = 42 x = 42/7 = 6
(3, 3)
79
7x + y + z = 6 7x + y + 4z = 9 y + x = 6 Take the first two statements and subtract them. 7x + y + z = 6 7x + y + 4z = 9 _____________ 0 + 0 - 3z = -3 Therefore: z = 1 Then you are left with: 7x + y + 1 = 6 7x + y + 4 = 9 which is impossible, so this is an impossible equation.