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What is the 49 times table?
1x49=49 2x49=98 3x49=147 4x49=196 5x49=245 6x49=294 7x49=343 8x49=392 9x49=441 10x49=490 11x49=539 12x49=588
There is a bus with 7 children inside. Each child has 7 bags. Inside each bag there are 7 big cats. Each big cat has 7 small cats. All cats have 4 legs each. How many legs are on the bus?
As a riddle, the answer is zero legs on the bus since the bus has wheels instead of legs.But as a maths problem; It's not a tricked question -- just a straightforward maths problemConfirmed answer is 10990 legs.§ Let's say the whole situation simply :- There are 7 girls.- Each girl has 7 backpack- Each backpack has 7 big cats- Each big cat has 7 little small cats.§ Question: How many legs are there in the bus?§ Let's focus on each part of the question systematically, write down on a piece of paper if you have to, following my steps of chains.1. Focus on the first girl first:A B C D E F GGirl A has 7 backpacks2. Now focus on first backpack A1 :A1 A2 A3 A4 A5 A6 A7Backpack A1 has 7 big cats3. Now focus on first big cat :1 2 3 4 5 6 7Ø Each big cats have 7 small cats (that's the end of the focus)Systematically, 7 small cats has 28 legs (7 * 4) combined with the big cat that owns this 7 small cats.Let's call this the "cat chain", so cat chain 1has 32 legs altogether.Ø So since there are 7 big cats7 * 32 = 224 legsØ Therefore each backpack has 224 legsØ Finally, each girl has 7 * 224 = 1568 legs.Lastly, since there are 7 girls, A to G, there are 7 * 1568 legs (per girl) = 10976 legs.Now, since each girl also has 2 legs each;SO, (7 * 2) + 10976 = 10990 legs altogetherNote: Disregarding bus driver, buses and etc…Only focus on the girl and their backpacks!Or There are 7*7 = 49 bags and there are 7 + 7*7 = 56 cats in each bag, meaning there are 56*4 = 224 legs in each bag. So including the 7 children that have 2 legs each, there are 7*2 + 49(224) = 10990 legs in total.
What is the solution to -7x49?
-7x49 = -(7x49) = -343
What is 7x49 equal?
the answer is 183
What cal is the fn fal?
7.62x51. Some early production rifles for Venezuela were manufactured in 7x49, but were later converted to 7.62x51.
What is the 49 times table?
1x49=49 2x49=98 3x49=147 4x49=196 5x49=245 6x49=294 7x49=343 8x49=392 9x49=441 10x49=490 11x49=539 12x49=588
There is a bus with 7 children inside. Each child has 7 bags. Inside each bag there are 7 big cats. Each big cat has 7 small cats. All cats have 4 legs each. How many legs are on the bus?
As a riddle, the answer is zero legs on the bus since the bus has wheels instead of legs.But as a maths problem; It's not a tricked question -- just a straightforward maths problemConfirmed answer is 10990 legs.§ Let's say the whole situation simply :- There are 7 girls.- Each girl has 7 backpack- Each backpack has 7 big cats- Each big cat has 7 little small cats.§ Question: How many legs are there in the bus?§ Let's focus on each part of the question systematically, write down on a piece of paper if you have to, following my steps of chains.1. Focus on the first girl first:A B C D E F GGirl A has 7 backpacks2. Now focus on first backpack A1 :A1 A2 A3 A4 A5 A6 A7Backpack A1 has 7 big cats3. Now focus on first big cat :1 2 3 4 5 6 7Ø Each big cats have 7 small cats (that's the end of the focus)Systematically, 7 small cats has 28 legs (7 * 4) combined with the big cat that owns this 7 small cats.Let's call this the "cat chain", so cat chain 1has 32 legs altogether.Ø So since there are 7 big cats7 * 32 = 224 legsØ Therefore each backpack has 224 legsØ Finally, each girl has 7 * 224 = 1568 legs.Lastly, since there are 7 girls, A to G, there are 7 * 1568 legs (per girl) = 10976 legs.Now, since each girl also has 2 legs each;SO, (7 * 2) + 10976 = 10990 legs altogetherNote: Disregarding bus driver, buses and etc…Only focus on the girl and their backpacks!Or There are 7*7 = 49 bags and there are 7 + 7*7 = 56 cats in each bag, meaning there are 56*4 = 224 legs in each bag. So including the 7 children that have 2 legs each, there are 7*2 + 49(224) = 10990 legs in total.
