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Q: What is -x plus 2y equals 6?

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Exactly (2y + 4) .

X+2y=6 how to solve? 2y=6-x then y=3-x so y=3-x

(x, y) = (-6, 0)

If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.

This means that 2y - 3 = 2y + 4 which is not possible.

-4

For 4x + 2y = 6The X intercept is 1.5The Y intercept is 3

The solution is (x, y, z) = (2.5, 1, 2.5).

2y(x+2)=

-2y=x+8 is the answer

x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?

x + 2y = x + 2y Y and X aren't compatibles.

x=2y-1

Subtract first from second gives -4x = 16 so x = -4 and y = -7

x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5

The values are: x = -6 and y = 10

x = -2 and y = 4 (-2,4)

The ordered pair is (1, 1).

x + 2y = 62y = -x + 6y = -1/2 x + 3

x+2y-6 = 0 2y=6-x y=3-x/2 the slope is -1/2 the y-intercept is 3

4x + 2y = 6 (first equation x 2) 4x + 2y = 6 (second equation rearranged) No unique answer exists

x = 3y - 3 so 6 (3y - 3) + 2y = -12 ie 18y - 18 + 2y = -12 ie 20y = 6 so y = 0.3 and x = -2.1

(3, 2)

x = 3 and y = 2

x = 0 & y = -3