Wiki User
∙ 14y ago31
Wiki User
∙ 14y ago5
x^2+5-6=0 (x+6)(x-1)=0 x=1,-6
It is 5.
1 plus 9, 2 plus 8, 3 plus 7, 4 plus 6, 5 plus 5, 6 plus 4, 7 plus 3, 8 plus 2, 9 plus 1, and 10 plus 0.
-5, -1, 0, 6
If you put the numbers in order it is: 0, 0, 1, 2, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 7, 7, 7, 8, 9. Since there are 25 numbers, we are looking for the thirteenth number, which is 5.
-6 - (-5) + 2 - 1 = -6 + 5 + 2 - 1 = -1 + 2 -1 = 1 - 1 = 0
102
10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 55
10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 55
5
x^2+5-6=0 (x+6)(x-1)=0 x=1,-6
120
solving for the x variable given that x2-6x+5=0 factoring the polynomial gives (x-1)(x-5)=0 which leaves you with your two answers, x=1, 5 or you could have used the quadratic equation x = [ -(-6) plus/minus sqrt( (-6)2 - 4*1*5 ) ] / (2*1) x = [ 6 plus/minus sqrt( 36-20 ) ] / 2 x = [ 6 plus/minus 4 ] / 2 x = 3 plus/minus 2 x = 5, 1
It equals 6
6+(-2)+3+5+(-7)+(-8)+4-1=0
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n