Q: Find a pair of whole numbers whose product is 280 and whose LCM is 140?

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3 and 84.

They are: 2 and 140

They are 2 and 140 because their LCM is 140 and their product is 280

10 and 12

33X34=1122 34-33=1

19

20 x 21 = 420

For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.

find two positive numbers whose product is a maximum. 1.) the sum is s.

The numbers are 18 and 20.

9 and 6

you are a nerd

8 and 5

They are: 4 and -3

10 and 3

24,25,26

Three and Seven

Multiply them together

Factors.

Multiplicand and Multiplier

When you have this kind of question, try to break it down, maybe first by a 2 or 3 or 10. For your question, find 3 numbers whose product is 320, the answer is 4x8x10=320. So the 3 numbers are 4, 8, and 10.

8 and 12

They are 16 and 18

xy = 147 x/y = 3 x = 21 y = 7

These two whole numbers are 34 and 36.To find the answers, you need to solve for the two variables A and B in the two equations [A plus B equals 70] and [A multiplied by B is equal to 1224]. You need to use the method of substitution to get the answers.

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