Any of its factors which are: 1, 3, 37 and 111
Itself and any of its other multiples (ex. 226, 339, etc.)
One and itself.
113, 226, 339, 452, 565 . . .
It is: 119/7 = 17
By 1 and 113.
1, 2, 4, 29, 58, 116
1 and 113
178 is divisible by ?
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
113 is already prime. No factorization.
They are one and itself because 113 is a prime number
Itself and one because 113 is a prime number
113 is a prime number. It is divisible only by 1 and itself.
No.
yes 113/3=37.666667
5, 113.
226 / 2 = 113
Just 1.
Yes but it will have a remainder of 1
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
Not evenly because there will be a remainder of 1
The number 113 is a prime number. It is not divisible by any number except 1 and itself.
By these factors: 1, 3, 9, 113, 339, 1017.
109 is divisble by 9