Q: What is 11 plus 8q equals 3q-19?

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q=-6

3q+11+8q>99

16p + 6q - 3p - 8q = (16p - 3p) + (6q - 8q) = 13p -2q

6p+11q+4

To solve an equation, the goal is to get the variable by itself. In this case the variable is q. -6=8q-4 first you want to get 8q by itself because the 8 and the q are together right now. So add 4 to each side to cancel it out on the side that has a -4. -6+4=8q simplify. -2=8q then to get rid of the 8, you have to divide both sides by 8 and then you get q by itself. -2/8=q simplify again. -1/4=q q=-1/4 :)

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q=-6

3q+11+8q>99

16p + 6q - 3p - 8q = (16p - 3p) + (6q - 8q) = 13p -2q

Only if the value of "q" is greater than 8.

It is equivalent to: -8q-28

3q+11+8q>99

3q + 11 + 8q > 99 11q + 11 > 99 Subtract '11' from both sides 11q > 99 - 11 11q > 88 Divide both sides by (+)11 q > 88/11 q > 8 ('q' is greater than '8'). Verification When q = 7 (8) 11(9) = 99 > 88 (True) 1

6p + 11q + 4

6p+11q+4

log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.

To solve an equation, the goal is to get the variable by itself. In this case the variable is q. -6=8q-4 first you want to get 8q by itself because the 8 and the q are together right now. So add 4 to each side to cancel it out on the side that has a -4. -6+4=8q simplify. -2=8q then to get rid of the 8, you have to divide both sides by 8 and then you get q by itself. -2/8=q simplify again. -1/4=q q=-1/4 :)

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