B evaluates to 8. Here is how the formula may look:
15 = 7 + b
Now we have to isolate the b. The easiest way is to subtract the 7. Remember that what we do to one side, we must do to the other side.
15 - 7 = 7 + b - 7
It is time to simplify. On the left we know that 15 minus 7 is 8. On the right, the +7 and the -7 cancel each other out and can all be removed. That leaves b.
8 = b
4b+3=15 4b=15-3 b=(15-3)/4 b=3
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
b + 7 = 18 subtract 7 from each side b + 7 - 7 = 18 - 7 b = 11 ----------------check in original equation 11 + 7 = 18 18 = 18 --------------checks
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
x=b-a
-7 7b + 15 = (-34) 7b = (-34) - 15 7b =(-49) b = (-49) / 7 b= (-7)
the answer is a
7b + 15= -34 First, 7b + 15 - 15 = -34 - 15 So, 7b = -49 Then, 7b/7 = -49/7 And finally, b = -7 So b = -7
3
The values of a and b are 7 and 18 or 18 and 7
b + b + b + 7 = 223b + 7 = 223b = 15b = 5
b=12
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
a = 6b = 9a + b = 6 + 9 = 15
15+b = 23 Subtract 15 from both sides b = 8
ax + b = 15 or ax + b = -15
A^2 + b = 7 A + B^2 =11 -------------- A=2 and B=34(2^2) + 3 = 7 2 + 9(3^2) = 11