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the remainder for 2x4 + 5x3 - 17x2 - 5 divided by x + 3

by the remainder theorem, to get the answer you first find the value of x tha t makes x + 3 = 0. That is x = -3.

You then substitute this value in the "numerator" expression:

Thus remainder = 2*(-3)4 + 5*(-3)3 - 17*(-3)2 - 5

= 2*81 - 5*27 - 17*9 - 5 = -131

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Q: What is the remainder when 2x4 5x3 - 17x2 - 5 is divided by x 3?

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Related questions

Quotient: 2x3-x2-14x+42 Remainder: -131 over (x+3)

3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2

4705.341 because 5x3=15x556=8340 divided by the square root of pi(1.7724539) is4705.314.

15 5x3 prime factorization: 5x3

None. 5x3 is a pure number, not a length.

What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3?

15

30

The answer is 21

5.3

no (5x3)

In the future, ask four questions as four separate questions to limit confusion. 6x7y4(2x4 - 5xy) could be written as 6x8y4(2x3 - 5y) Either way, once you carry out the multiplication, it becomes 12x11y4 - 30x8y5 I'm guessing the second problem is 25x9 - 10x3 + 5x3 since this website can't reproduce plus signs. That becomes 25x9 - 5x3 which factors to 5x3(5x6 - 1) x^2 and -x^2 cancel each other out, leaving 3549 - 12x which factors to 3(1183 - 4x) -7x^2 - 3x - 21 can be written as -(7x^2 + 3x + 21) but the solution isn't rational.

-5

An expression. It can be factored out slightly too: 2x6 + 5x3 - 7x4 = x3(2x3 - 7x + 5)

20 divided by 4 is 5; 5x3=15 A quarter is 25% or one fourth of a number.

5x3

2(10x6) 4(5x3)

5x3=15 is the inverse

The GCF is 5x

5(x3 - 3x2 - 238)

It is a quadratic expression

y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.

Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)

The generalisation is that multiplication is Abelian (or commutative) for numbers.

5" x 3" = 15 square inches.