By usual definitions of outliers, there is none.
you play on the 5th and 6th strings: 6:-7-10-12-15/14/15/14/15-7-7-10-10 5:-9-12-14-17/16/17/16/17-9-9-12-12
12, 14, 15, 16.
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20
10, 12, 14, 15, 16, 18, 20.
(21+15+19+28+10+17+9+15+26+14+10+18+24+12+16) / 15 = 16.93 recurring (that is, 16.93333...)
16
The median of {10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] is the 6th values which is 15.
10, 12, 14, 15, 16, 18, 20
10, 12, 14, 15, 16, 18, 20
10, 12, 14, 15, 16, 18, 20
10, 12, 14, 15, 16, 18, 20