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Q: What is the nth term of 1 8 15 22 29?

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It is: nth term = 29-7n

The nth term is -7n+29 and so the next term will be -6

t(n) = 29 - 7n where n = 1, 2, 3, ...

76

is 219 in the sequence of 4n-3

The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.

nth term = 5 +8n

2n +29

5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62

9n+2

35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1

As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1

29. To find range, you subtract the lowest term, from the largest term. 39-10=29

-22 -6 0 15 29

29

Un = 29 - 9n

5, 11, 17, 23, 29

The (n)th term = the (n - 1)th term + (2n + 1)

The nth term of the sequence -4 4 12 20 29 is 8n+12 because each time the sequence is adding 8 which is where the 8n comes from. Then you take 8 away from -4 and because a - and - equal a + the answer is 12. Which is where the 12 comes from. Hope I helped.

t(n) = 12*n + 5

It is 6n+5 and so the next term will be 35

It is increasing by 4 and the nth term is 4n+1

It is T(n) = n2 - 2n + 6

-29

29

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