The multiplication problem 12 times 56 is approximately 784.
The least common multiple of 2, 3, 4, 5, and 6 is 60.
A multiple of 6 because you can get a 6 and 6, a 1 and 5, a 2 and 4, and a 3 and 3. The only factors you can get are 2, 3, and 6.
The first 6 multiples of 1 are: 1, 2, 3, 4, 5, and 6.
They are: 1, 2, 3, 4, 5, 6, 7.
Multiples of 7 (first 5) : 7, 14, 28, 35Multiples of 5 (first 7) : 5, 10, 15, 20, 25, 30, 35The least common is then 35.
Least Common Multiple (LCM) for 5 4 6 is 60
10 is a multiple of 1, 2 and 5 from the given numbers
The least common multiple of 4 , 10 , 5 , 6 = 60
The least common multiple of 2, 3, 4, 5, and 6 is 60.
Since there are no multiples of 5 that are factors of 36, that's a two-part question. 4 x 3 - 6 - 1 = 5, a multiple of 5. 4 x 3 + 6 x 1 = 18, a factor of 36.
No.
Any multiple of 60.
Since 36 doesn't have any factors that are multiples of 5, you're looking for two different groupings. 4 x 3 - 6 - 1 = 5, which is a multiple of 5. 4 x 3 + 6 x 1 = 18, which is a factor of 36.
Out of that list, just 1, 2 and 5.
lcm(4, 5, 6) = 60
It is: 3*5 = 15
The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6=1/3 = 0.333... ≈ 33.3%.The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%