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Q: What is 1 plus 2 plus 3 plus 4. plus 98 plus 99 plus 100?

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100 + 99 + 98 + 2 + 1 + 0.3 = 300.3

303

505

1 + 98 = 99

1 + 99 = 100

100

1 +100 = 101 100 - 1 = 99 99 +1 = 100 100 times 100 =10000 10000 divide by 2 = 5050Ans:5050

99 + 1 = 100

Since 1+99=100. And 2+98=100 and 3+97=100 etc to 49+51=100 it's 49 of those plus 50 or 4,950. The sum of the first 99 whole numbers is 4,950

99+1=100

2 x 50 = 100 2 x 49 = 98 99 - 98 = 1 Answer: 49 times with 1 remaining

100

printf ("%s\n", "1, 2, 3, 4, 5, 6, ..., 98, 99, 100"); printf ("%s\n", "100, 99, 98, 97, ..., 3, 2, 1");

100

1 + 99 = 100 2 + 98 = 100 3 + 97 = 100 4 + 96 = 100, etc untll you got to 49 + 51 = 100 There would be 49 of these "=100" answers (That would be 4,900) Plus, you would have 50 left over with nothing to match up to. So your total would be 4,950.

197

Right now, the percentage of boys is [ 99/(99+1) ] = (99/100) = 99% If 50 boys leave, then the percentage of boys is [ 49/(49+1) ] = (49/50) = 98%

Sum of numbers from 1 to 100:(1+100) + (2+99) + (3+98) + (4+97) + ... + (49+52) + (50+51) =50 pairs, each pair adds up to 101= (50 x 101)= 5,050

The answer is 409. Simply add the numbers together like you would for two plus two. To check your work, a calculator is the best option.

99 or 100 or 98

There are infinitely many sets: For example, -99, -98, -97, ... -2, -1, 0, 1, 2, ... 97, 98, 99, 100 or 1, 1, 1, 1 ... [100 times] or 0.0001, 0.0001, 0.0001, ... [ a million times].

100-1-1-1= 99-1-1= 98-1= 97 ..... ..... ..... ..... ..... ..... ..... ..... 100-1-1-1= 100-3= 97

(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.

It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.

98+1 100-1 97+2 96+3 93+6