3n + 6 = n + 202n = 14n = 7
An even number is represented by 2n.Let the first number be 2n, and the second number be 2n + 2. So we have,2n + 2n + 2 = 824n + 2 = 82 subtract 2 to both sides4n = 80 divide by 4 to both sidesn = 202n = 2 x 20 = 402n + 2 = 40 + 2 = 42Thus, the two consecutive even numbers are 40 and 42.
Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:2n + (2n + 2) = (2n + 4) + 164n + 2 = 2n + 202n = 18 the smallest integer2n + 2 = 18 + 2 = 20 the next one2n + 4 = 18 + 4 = 22 the largest integerCheck