Q: What is 2058 plus 245 plus 28 plus 2?

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The prime factors of 2058 are 2*3*7*7*7, or 2 × 3 × 73.

The prime factorization of 2058 is 2 x 3 x 7 x 7 x 7 or 2 x 3 x 73.

-2 + 28 = 26

-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2

28*6+2= 170 Thank you

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The prime factors of 2058 are 2*3*7*7*7, or 2 × 3 × 73.

The prime factorization of 2058 is 2 x 3 x 7 x 7 x 7 or 2 x 3 x 73.

It is 2+28 = 30

-2 + 28 = 26

2 x 3 x 7 x 7 x 7 = 2058

1/7 + 1/2 + 5/28 = 4/28 + 14/28 + 5/28 = 23/28

-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2

28*6+2= 170 Thank you

120 + 13 + 3 + 8 + 2 + 2 + 353 + 42 + 20 + 28 + 87 + 8 + 10 = 696

Do you mean, 2 + 3^x = 245 ?? 2 + 3^x = 245 subtract 2 from each side 3^x = 243 use natural logs ( I always do, though you can use logs ) ln(3^x) = ln(243) you have the right in this operation to bring the exponent before the natural log x(ln3) = ln(243) divide x = ln(243)/ln(3) ( not ln(243/3) !!!! ) x = 5.493061443/1.098612289 x = 5 ----------check 2 + 3^5 = 245 2 + 243 = 245 245 = 245 ===========checks

16 + 24/2 = 28/1 or 28

122.5