The partial products are: 42 * 28 = (40 + 2)*(20 + 8) = 40*20 + 40*8 + 2*20 + 2*8 = 800 + 320 + 40 + 16
The partial products are 40*20 + 40*8 + 20*2 + 2*8 = 800 + 320 + 40 + 16 = 1176.
How many times do you subtract 2 from 11?
6/63=3(2)/3(21)=2/21 2/21 times.
42 ÷ 21 = 2
the partial products for 84 and 78 6000,500,50,and 2 :)
2877.5
The partial products are: 42 * 28 = (40 + 2)*(20 + 8) = 40*20 + 40*8 + 2*20 + 2*8 = 800 + 320 + 40 + 16
The partial products are 40*20 + 40*8 + 20*2 + 2*8 = 800 + 320 + 40 + 16 = 1176.
As a product of its prime factors: 2*5*563 = 5630
2/7 times 21 = 6
They are: 30*20, 30*8, 2*20 and 2*8.
How many times do you subtract 2 from 11?
441 x 2 = 882
6/63=3(2)/3(21)=2/21 2/21 times.
2/7 times 21 = 6
42 ÷ 21 = 2