27 times 15 is equal to 405
Wiki User
∙ 2012-05-29 00:55:49102,060
15 with remainder 15.
All multiples of the lowest common multiple of 15 and 27 are in both their times tables. The lcm of 15 and 27 is 135, so all multiples of 135 are in both the 15 and 27 times tables: 135, 270, 405, 540, 675, 810, 945, 1080, 1215, 1350, ...
9 times
In the problem 2x-3 is 27, the x is equal to 15. Two times 15 is 30 and -3 is 27.
3(5-x) = 27 15 - 3x = 27 15 - 3x + 3x = 27 + 3x 15 = 27 + 3x 15 - 27 = 27 - 27 + 3x -12 = 3x -4 = x To check 3(5- -4) ? 27 15 - -12 ? 27 15 + 12 = 27
15
15 times and 27 times respectively
139/27 or 5 and 4/27
27 * 5 / 18 = 15/2 = 7.5
5 with remainder 15.
1 with remainder 15.