(x squared plus the square root of 2) times (x squared minus the square root of 2).
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.
x = the square root of -2
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
(a + x^2)(b + y^2)
The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.
3 squared plus 2 squared is equal to 13.
It is 8
9 plus 2 squared is equal to 13.
X + y
It's the square root of the sum 18 feet squared plus 18 feet squared. 18 feet squared is 324 square feet. 2 x 324 square feet = 648 square feet. The square root of 648 square feet is about 25.46 feet.
If it is (x+x)2 then it is (2x)2 and the sqrt of that is 2x.
(a+b)^2=a^2+b^2+2ab it should read "the quanitity "a plus b" squared equals a squared plus b squared plus two a times b" See related link below for a picture that shows it graphically.
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
9t2 + 42t + 49 is a perfect square, equal to (3t + 7)2
(a + 2 - b) (a + 2 + b)
8 = 4 + 4 = 2² + 2²
When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.
1 squared plus 8 squared or 4 squared plus 7 squared