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Q: What is p plus 3p plus 2q plus 5q?

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simply add the like terms: 4p -3p +2q -2q = p

It is a string of algebraic terms.

2(2p + 5q)

5*(2q + 5r)

In its general form it works out as: 3px+qy-12p2-2q2 = 0Improved Answer:-Points:(p, q) and (7p, 3q)Slope: q/3pPerpendicular slope: -3p/qMidpoint: (4p, 2q)Equation: y-2q = -3p/q(x-4p) => yq = -3px+12p2+2q2Perpendicular bisector equation in its general form: 3px+qy-12x2-2q2 = 0

7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)

6p + 12q + 18r = 6 (p + 2q + 3r)

6

It is an expression that can be simplified to: 3p+q

Rprime= 2q + 2a + 3 Rdoubleprime= 4

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared". There is no symbol between 15 and 3p.

p=-1

They are both Pathfinder. F7 is Enlisted, 5Q is officer.

It is an equation with the plus or minus signs missing which makes it impossible to solve.

The question is incomplete in the sense that there is no +/- sign between q2 and 2q. Considering plus '+' sign. q3 - q2 + 2q - 2 q2(q - 1) + 2(q - 1) (q2 + 2)(q - 1) Considering minus '-' sign. q3 - q2 - 2q - 2 The expression can't be factored. However if we consider the question complete then it is written as: q3 - q2(2q) - 2 q3 - 2q3 - 2 -q3 - 2 -(q + 21/3)(q2 - 21/3 + 22/3)

answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}

2q

3p - 6 > 21 3p - 6+6 > 21+6 3p > 27 3p/3 > 27/3 p>9 this WILL help

2p+4q=16 (now divide the equation by two) p+2q=8 (now subtract 2q) p=8-2q 7p+12q=52 (substitue the answer you got for p in the previous equation) 7(8-2q)+12q=52 (multiply the first equation by 7) 56-14q+12q=52 (subtract 14q from 12q) 56-2q=52 (subtract the 56 from 52) -2q=-4 (multiply by -1) 2q=4 (divide by 2) q=2 p=8-2q (substitute the value of q) p=8-2(2) (multiply) p=8-4 (subtract) p=4 2p+4q=16 (check your answers with the new values of p and q) 2(4)+4(2)=16 8+8=16 true 7p+12q=52 7(4)+12(2)=52 28+24=52 true

2 quarts ice cream

3p9

If: 6p-2-3p = 16 Then: p = 6

Al, Si, P, S, Cl and Ar have 1, 2, 3, 4, 5 and 6 electrons respectively in the 3p (valence orbitals). However all elements after Argon have completely filled 3p orbitals though 3p is not the valence orbital.

9

p2 + 3p - 4What two factors of - 4 add up to 3 ??(p - 1)(p + 4)===============so,p = 1p = - 4

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