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What is six and one fifth plus one and three forth?
61/5 + 13/4 = 6x5+1/5 + 1x4+3/4 = 31/5 + 7/4 = 31x4/5x4 + 7x5/4x5 = 124/20 + 35/20 = 159/20 = 7x20+19/20 = 719/20
What is the gram molecular mass of phosphorous?
The atomic mass of phosphurus is 31. The atomic mass of chlorine is 35.5. Therefore, the gram molecular mass of PCl3 is 31+3x35.5=137.5 grams per mole.
What are the rules for positive integral exponent?
There are 5 laws: Product Law: This is when the same bases are being multiplied ex. 83 X 82 this is the same as 8x8x8 8x8 when the same bases are being multiplied you just add the exponents so the answer would be 85 Quotient Law: This is when the same bases are being divided. ex. 83 divided by 82 in other words 8x8x8 divided by 8x8 when the same bases are being divided you just subtract the exponents so the answer would be 81 Power of product law: here is an example : (8x3)2 in this problem all you have to do is apply the exponent to each number in side the bracket or multiply the exponent to each exponent inside the brackets, if there is no exponent you assume there is a 1 so you would do 8 1x2 and 3 1x2 and the answer would be 82x32 Power of quotient law: this is the same as the one above, you basically just multiply the exponent to the numbers inside the brackets. So if it was (8 divided by 3)4 you would assume there is an exponent 1 for both the numbers and multiply by four. 8 1x4 divided by 31x4 = 84 divided by 34 Power of a power law: What do you do if there is already an exponent inside the brackets? ex. (84)5 you would do the same thing. You multiply the exponents! if you put the question in standard form it is 8x8x8x8 repeated five times 8x8x8x8 8x8x8x8 8x8x8x8 8x8x8x8 8x8x8x8 how many 8s are there? 20 how do you solve in a much simpler way? you do 84x5 and get the 820
2x-3 parenthesis 2x plus 3 parenthesis equals?
(2x-3)(2x+3) can be multiplied out using the FOIL method, which stands for:FirstOuterInnerLastThis method only works for the multiplication of two binomials, so don't rely exclusively upon it.For the "first" part, multiply the two first terms of the binomials together:(2x)(2x)=4x2For the "outer" part, multiply the two outermost terms together:(2x)(3)=6xFor the "inner" part, mulitply the two innermost terms together:(2x)(-3)=-6xFor the "last" part, mulitply the two last terms of each binomial together:(3)(-3)=-9Add all of these sub-calculations together to get your final result:4x2+6x-6x-9As you can see, 6x-6x=0, so these two terms will cancel out, leaving:4x2-9Another way of doing this multiplication is to see it as an application of the distributive property, but instead of a single number distributed across a binomial, it is another binomial. This is what the FOIL method essentially does, but it creates a handy mnemonic to remember it. To see it as a distributive problem, visualize it like this as I distribute (2x-3) across (2x+3):(2x-3)(2x+3)=(2x-3)(2x)+(2x-3)(3)=(4x2-6x)+(6x-9)=4x2-9As you can see, the same answer is reached. This method of distributing one entire term across the other polynomial holds true for more complicated multiplications, so it is the most accurate way to memorize how to handle these problems. A simplification of something like this:(x-7)(5x4+4x3-x2+9x-2)cannot be handled with such a convenient crutch as the FOIL method, but realizing it is simply distribution makes it very doable:(x-7)(5x4)+(x-7)(4x3)-(x-7)(x2)+(x-7)(9x)-(x-7)(2)(5x5-35x4)+(4x4-28x3)-(x3-7x2)+(9x2-63x)-(2x-14)5x5-35x4+4x4-28x3-x3+7x2+9x2-63x-2x+145x5-31x4-29x3+16x2-65x+14And in case that side-track example distracted you from the real answer, it was 4x2-9
