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Llewellyn Hermiston
Wiki User
∙ 6y agoThis is an incomplete problem. The variable 'x' can be replaced by any number - and there is no result stated.
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What is the least number that is a multiple of both 3and 4show the work?
To find the least common multiple you need to find the multiples of each number first until you find a match. To find the multiples just multiply each number by whole numbers until you find the match.3x1=34x1=43 and 4 dont match...3x2=64x2=83,4,6, or 8 dont match.3x3=94x3=123,4,6,8,9, or 12 dont match...3x4=124x4=16You found the match... 3x4=12 and 4x3=12 so the LCM is 12This is how I would do it quickly without showing all of the multiplication. I am just going to show the multiples...multiples of 3 - 3 6 9 12 15 18 21multiples of 4 - 4 8 12 16 20 24 28As you can see 12 is the lowest common multiple. This is the fast way to do it if you can do the multiplication in your head.
Whair can you find an huge multiplycation chart?
Here up until 12's :) Look :0x1=01x1=12x1=23x1=34x1=45x1=56x1=67x1=78x1=89x1=910x1=1011x1=1112x1=12TWO'S0x2=01x2=22x2=43x2=64x2=85x2=106x2=127x2=148x2=169x2=1810x2=2011x2=2212x2=24THREE'S0x3=01x3=32x3=63x3=94x3=125x3=156x3=187x3=218x3=249x3=2710x3=3011x3=3312x3=36FOUR'S0x4=01x4=42x4=83x4=124x4=165x4=206x4=247x4=288x4=329x4=3610x4=4011x4=4412x4=48FIVES0x5=01x5=52x5=103x5=154x5=205x5=256x5=307x5=358x5=409x5=4510x5=5011x5=5512x5=60SIX'S1x6=62x6=123x6=184x6=245x6=306x6=367x6=428x6=489x6=5410x6=6011x6=6612x6=72SEVEN'S1x7=72x7=143x7=214x7=285x7=356x7=427x7=498x7=569x7=6310x7=7011x7=7712x7=84EIGHT'S1x8=82x8=163x8=244x8=325x8=406x8=487x8=568x8=649x8=7210x8=8011x8=8812x8=96NINE'S0x9=01x9=92x9=183x9=274x9=365x9=456x9=547x9=638x9=729x9=8110x9=9011x9=9912x9=108TEN'S1x10=102x10=203x10=304x10=405x10=506x10=607x10=708x10=809x10=9010x10=10011x10=11012x10=120ELEVEN'S1x11=112x11=223x11=334x11=445x11=556x11=667x11=778x11=889x11=9910x11=11011x11=12112x11=132TWELVE'S1x12=122x12=243x12=364x12=485x12=606x12=727x12=848x12=969x12=10810x12=12011x12=13212x12=144
