.38 inches is 19/50 of an inch.
38 inches X 2.54 cm/inch = 97 cm
38 in = 965.2mm
It is customary to call a circle a 38 inch circle if its diameter is 38 inches. If that is the case, the radius = diameter/2 = 19 inches.
38 centimeters=14.9606299 inches
38 inches = 0.9652 meters.
38 inch = 96.52 centimeter
This might get a little confusing. A TRUE .38 caliber cartridge will be 38/100ths of an inch in diameter. HOWEVER, the cartridge CALLED the .38 Special is not quite that large- it is .357 inches in diameter, or 357/100ths of an inch- just over a third of an inch, or a little more than 9 millimeters.
From a 32 inch to a 38 inch in 1977
Equals (55/2.54) inch x (38/2.54) inch x (20/2.54) inch
It is 119.38052083641213.
The answer depends on whether it is the linear dimensions that are increased by 38% or the area.
No, it is way too big for a pilot hole as 5 mm = 0.20 inch which is smaller than .38 inch
The width of a 700 times 38 inch in mm would 622mm. This is math.
They measure the width of the gun barrel in fractions of an inch. A 38 caliber will be .38 of an inch. The bullet projectile itself is a little less wide.
36DD 26 inch waist and 38 inch hips
32 of them.
12 inch diameter(also 6 inch radius).
38 inches is close to 1 (0.9652) meter.
Even though it's called a .38, it's actually .357 of an inch in diameter.
Its about .355 thousandths of an inch, roughly 36 caliber. One would think it would be closer to 38 caliber (.38 hundredths of an inch) but that might refer to the diameter of the brass case the holds the bullet. In other parts of the world, .380 is called 9mm Short. Even the revolver round .38 Special is actually 357 thousands of an inch, not 38.