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Q: What is 3 n plus 4 n plus 7 plus 3?

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3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2

The value of n is 3, by the commutative property.

For n = 1, 2, 3, 4, 5, ... the sequence goes 4, 5, 6, 7, 8, ...

No. If your trying to find n, then you subtract four from each side. n = 10 That would be subtraction property of equality.

(n2 + n)/2 1+2+3+4+5+n= 15+n

3n + 9 = 3(n + 3)

If n = 7, then 5n + 4 = 5 x 7 + 4 = 39.

3n + 4 = 7(- 4 from both sides)3n = 3(divide both sides by 3)n = 1

Yes. Multiplying out the brackets on the second one: 4(n + 3) = 4×n + 4×3 = 4n + 12.

3 + 7 is an ADDITION sum

n + 7 = 10subtract 7 from both sidesn = 3

7 - 3n: n = 0: 7-3(0) = 7 n = 1: 7-3(1) = 4 n = 2: 7-3(2) = 1 n = 3: 7-3(3) = - 2 n = 4: 7-3(4) = - 5 n = 5: 7-3(5) = - 8

-n/7+19=-3 -n/7=-22 n/7=22 n=22(7) n=154

N = -36

If: n--3 = -4 Then: n = -7

6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n

2+n-3 = 6 n = 6+3-2 n= 7

-9 + n/4 = -7 Add 9 to both sides: n/4 = +2 Multiply both sides by 4: n = 8

Yes, it can. ANY equation of this form can be factored. The factors may not be integers or even real numbers, though.

n= -2

n ___ = 3 2+5 n = 3(2+5) n = 3(7) n = 21

2222= 3 mod 7 5555 = 4 mod 7 2222^5555 + 5555^2222 = (3^5)^1111 + (4^2)^ 1111 as it is a^n + b^n and n is odd so it is divisible by (a+b) 3^5 + 4^ 2 = 259 hence by 7 as 7 is a factor of 259

n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).

52 = 4 + (n-1)3 → 3(n-1) = 48 → n - 1 = 16 → n = 17

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