#include<stdio.h> #include<conio.h> main() { int a[4][4],b[4][4],c[4][4],i,j; printf("enter the elements of matrix a"); for(i=0;i<=3;i++) for(j=0;j<=3;j++) scanf("%d",&a[i][j]); printf("the first matris is"); for(i=0;i<=3;i++) { printf("\n"); for(j=0;j<=3;j++) printf("%d",a[i][j]); } printf("Enter the elements of second matrix"); for(i=0;i<=3;i++) for(j=0;j<=3;j++) scanf("%d",&b[i][j]); printf("the second matrix is"); for(i=0;i<=3;i++) { printf("\n"); for(j=0;j<=3;j++) printf("%d",b[i][j]); } for(i=0;i<=4;i++) for(j=0;j<=4;j++) c[i][j]=a[i][j] + b[i][j]; printf("the addition of matrix is"); for(i=0;i<=3;i++) { for(j=0;j<=3;j++) printf("%d\t",c[i][j]); printf("\n"); } getch(); }
#include<stdio.h> int main(){ int a[3][3],b[3][3],c[3][3],i,j; printf("Enter the First matrix->"); for(i=0;i<3;i++) for(j=0;j<3;j++) scanf("%d",&a[i][j]); printf("\nEnter the Second matrix->"); for(i=0;i<3;i++) for(j=0;j<3;j++) scanf("%d",&b[i][j]); printf("\nThe First matrix is\n"); for(i=0;i<3;i++){ printf("\n"); for(j=0;j<3;j++) printf("%d\t",a[i][j]); } printf("\nThe Second matrix is\n"); for(i=0;i<3;i++){ printf("\n"); for(j=0;j<3;j++) printf("%d\t",b[i][j]); } for(i=0;i<3;i++) for(j=0;j<3;j++) c[i][j]=a[i][j]+b[i][j]; printf("\nThe Addition of two matrix is\n"); for(i=0;i<3;i++){ printf("\n"); for(j=0;j<3;j++) printf("%d\t",c[i][j]); } return 0; }
#include<stdio.h> void main() { int a[3][3],b[3][3],c[3][3],i,j,k; clrscr(); printf("Enter elements of A:"); for(i=0;i<=2;i++) for(j=0;j<=2;j++) scanf("%d",&a[i][j]); printf("Enter elements of B:"); for(i=0;i<=2;i++) for(j=0;j<=2;j++) scanf("%d",&b[i][j]); printf("A:"); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) printf("%d ",a[i][j]); printf(""); //To change line. } printf("B:"); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) printf("%d ",b[i][j]); printf(""); } k=0; while(k<=2) { for(i=0;i<=2;i++) { int sum=0; for(j=0;j<=2;j++) sum=sum+a[i][j]*b[j][k]; c[i][k]=sum; } k++; } printf("Result: "); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) printf("%d ",c[i][j]); printf(""); } getch(); }
#include<stdio.h> main() { printf("Enter Order Of The Matrix\n"); int l,m; int i,j,k,t,x; scanf("%d%d",&l,&m); int a[l][m],temp[l*m]; printf("Enter The Elements Row Wise...\n"); for(i=0;i<l;i++) { for(j=0;j<m;j++) { scanf("%d",&a[i][j]); } } printf("Matrix A \n "); for(i=0;i<l;i++) { printf("\n"); for(j=0;j<m;j++) { printf("%d\t",a[i][j]); } } /*----------------------------------------------------------------------*/ x=0; for(i=0;i<l;i++) { for(j=0;j<m;j++) { temp[x]=a[i][j]; x++; } } for(i=0;i<l*m;i++) { for(j=0;j<(l*m)-1;j++) { if(temp[j]>temp[j+1]) { t=temp[j]; temp[j]=temp[j+1]; temp[j+1]=t; } } } x=0; for(i=0;i<l;i++) { for(j=0;j<m;j++) { a[i][j]=temp[x]; x++; } } printf("\nMatrix A After Sort \n "); for(i=0;i<l;i++) { printf("\n"); for(j=0;j<m;j++) { printf("%d\t",a[i][j]); } } }
#include<stdio.h> #include<conio.h> void main() { int i,a[3][3]={1,2,3,4,5,6,7,8,9},j,s=0,m,n; clrscr(); /*for(i=0;i<3;i++) { for(j=0;j<3;j++) { printf("\na[%d][%d]= ",i,j); scanf("%d",&a[i][j]); } }*/ for(i=0;i<3;i++) { for(j=0;j<3;j++) { printf("%d",a[i][j]); } printf("\n\n"); } for(i=0;i<3;i++) { for(j=0;j<3;j++) s=s+a[i][j]; printf("\n Sum of %d`th row=%d",i+1,s); s=0; } { int i,j,s=0; for(j=0;j<3;j++) { for(i=0;i<3;i++) s=s+a[i][j]; printf("\n\t\t Sum of %d`th column=%d",j+1,s); s=0 ; } } getch(); }
4184 miles X 5280 ft/mile = 22,091,521 feet
Answer: 4184 miles = 6733.495 km
The Bold and the Beautiful - 1987 1-4184 was released on: USA: 2 December 2003
4,184 feet = 1,275.28 meters
4,184 feet = 1,275.2832 meters
Curb weight 4184 lbs
184,999.99989344 in 185 kcals 1 joule = 0.239005736 calories 1 kilocalorie (kcal) = 4184 joules 185kl x 4184 Joules x 0.239005736 calories = 184,999.99989344
Quarry Town, Missouri, pop. 4184
The specific heat of water is 4184 J kg-1 K-1 The specific heat of copper 385 J kg-1 K-1. So the answer is no.
16,736 since 1calorie= 4184 joules.
the river nile is 6695 km long and in miles that would be 4184 miles
The efficiency of a heat engine is given by n = Wu / QH Where Wu - is the useful work (7190 J) QH - Heat taken from the hot reservoir (13,8 x 4184 J) 1 cal = 4,184 J => 1 kcal = 1000 cal = 4184J So n = 7190 / (13,8 x 4,184 x 1000) J and since you want that in percent multiply the result by 100.