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Q: What is 2a squared minus 5a minus 3 factored out?

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2a-5

2a+5

2a + 11a - 5a = 8a

No

2a + 3a = 5a

2a

(5a+8) - (2a+4) =3a +4 To do this, simply subtract like terms. 5a-2a=3a and 8-4=4

5a- 2a = 3

2a - 5a = -3a

It simplifies to 5a+4 !

It is: 2a+5a = 7a when simplified

2a-8+4=45-5a 2a-4=45-5a 2a-4+4=45+4-5a 2a+5a=49-5a+5a 7a=49 / by 7 = A=7

The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)

(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)

assuming 5a-a-2a-18=0 2a-18=0 2a=18 and thus a=9

Add them together: 2a+5a = 7a

9a +8 -2a -3 -5a = 2a +5

2a+5a+9a = 16a

2a + 5a + 3a = 10a

2a + 10 + 5a - 2 = (2a + 5a) + (10 - 2) = 7a + 8

5a or 4a squared

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a

5a + 4b - 3a =(5a - 3a) + 4b =2a + 4b =2 (a + 2b)

7

5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1