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It is 45/1.
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What fraction of a meter is 45 centimeters?
100 cm = 1 metre so 45 cm = 45/100 metre = 9/20 m
How do you convert 36 cm per sec to m per min?
To convert cm to m divide by 100 To convert s to min divide by 60 → 36 cm/s = 36 × (1 cm)/(1 s) = 36 × (1 ÷ 100 m )/(1 ÷ 60 min) = 36 × (1/100 m ÷ 1/60 min) = 36 × 60/100 m/min = 21.6 m/min
8h 30 min -4h 55min?
8 h 30 min =7h 100 m 7h 100min-4h 55 min=3h 45 min
What is the average speed on an ant that crawls 1 m in 45 seconds?
1/45 m/s
How many m are in 45 km?
1 kilometre = 1000 metres so 45 km - 45*1000m = 45000 m. Simple!
What fraction is 45 cmof 1 m?
It is 45/100.
What fraction of a meter is 45 centimeters?
100 cm = 1 metre so 45 cm = 45/100 metre = 9/20 m
How do you convert 36 cm per sec to m per min?
To convert cm to m divide by 100 To convert s to min divide by 60 → 36 cm/s = 36 × (1 cm)/(1 s) = 36 × (1 ÷ 100 m )/(1 ÷ 60 min) = 36 × (1/100 m ÷ 1/60 min) = 36 × 60/100 m/min = 21.6 m/min
8h 30 min -4h 55min?
8 h 30 min =7h 100 m 7h 100min-4h 55 min=3h 45 min
What fraction of 200 m of 1 km?
200 m /1 km = 200 m/1000 m = 1/5
A car travels 60 km in 45 minutes A second car travels 3 times the distance in four times the time What is the speed of the second car in meters per second?
60 km * 3 = 180 km 45 min * 4 = 180 min 180km/180hr = 1 km/min 1km = 1000m 1 min = 60s 1000m/60s = 16.67 m/s
What is the average speed on an ant that crawls 1 m in 45 seconds?
1/45 m/s
45 meters is how many square feet?
0.3048 m = 1 ft (exactly) 1 sq ft = 1 ft x 1 ft = 0.3048 m x 0.3048 m = 0.30482 sq m → 45 sq m = 45 ÷ 0.30482 sq ft ≈ 484 sq ft
What is 1 m as a fraction of 1km?
It is: 1/1000
What is a fraction of 1 km is M?
1/1000
What fraction of 1 m is 1mm?
It is: 1/1000
For the reaction A to Products successive half lives are observed to be 10 min and 40 min A was 0.10 M at the beginning of the reaction What is the integrated rate law and what is the rate constant?
Half-life in this context is defined as the time needed to observe the halving of the original reactant concentration. As you can see, in this case that time doubles each time, so you can say that this particular reaction as a second order rate. The equation for this half-life is: t(1/2) = 1/([A]0 * k) and the integrated rate eq. is: 1/[A] = 1/[A]0 + kt Using the first half life we can calculate k: k = 1/( t(1/2) * [A]0) = 1/(10 min * 0.50 M) = 0.2 min^-1M^-1 Using this value we can calculate the answers for a) and b) a) 1/[A] = 1 / [A]0 + kt = 1 / 0.50 M + .2 min^-1M^-1 * 80 min = 18 M^-1 [A] = 0.056 M b) 1/[A] = 1 / [A]0 + kt = 1 / 0.50 M + .2 min^-1M^-1 * 10 min = 4 M^-1 [A] = 0.25 M
