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Q: What is the complementary set for x the unit's digit of x is 0?

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The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.

When the tens digit is even and the units digit is 0, 4 or 8 or the tens digit is odd and the units digit is 2 or 6.

The nth triangular number is given by ½ × n × (n+1)→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.------------------------------------------------------------Alternatively,If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:If the tens digit is even (ie one of {0, 2, 4, 6, 8}), the remainder is the units digitIf the tens digit is odd (ie one of {1, 3, 5, 7, 9}), the remainder is the units digit + 10.5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.

The answer is 0 because anything multiplied by 0 is 0. This can be established using the set theory. If each set contains 8 units, but you have no sets at all (0), then you have 0 units. No matter how large a set is, having no sets means that you have no units.

A number is divisible by 20 if and only if it is an integer, its units digit is 0, and its tens digit is even.

The digit in the units column of the number 60 is the 0.

Any integer whose units' digit is 0.

If the digit in the tens place is divisible by 2 and the digit in the units place is a 0, then the number is divisible by twenty.

0 Look at the product of the first 3 prime numbers: 2 x 3 x 5 = 30. Any number multiplied by 30 will have a 0 in the units digit. So, no matter how many prime numbers you are multiplying, if once you have a number ending in 0, all of the rest will end in 0.

You test if the last two digits are divisible by 4. If the digit in the tens' place is odd, the digit in the units place must be 2 or 6. If the digit in the tens' place is even, the digit in the units place must be 0, 4 or 8.

3^333 ~ 7.61e+158 and is beyond the range of most calculators. I think "0" would be in the unit digit place.

They first has a greater probability. This is because the first digit comes from a set of 9: {1,2,3,4,5,6,7,8,9} while the second comes from that same set AND 0.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.

yes.0 is a digit because if 0 is in 10,why wouldn`t 0 be a digit.

Any two digit number in which: (a) the units digit is not 0, and (b) the two digits are different will form a new 2-digit number when the digits are interchanged.

10 You can only have one choice, the number 4 as the hundred digit and also one choice, the number 5 as the units digit. However, you can have any integer from 0-9 as the hundreds digit. The number of combinations is thus 1 x 10 x 1 = 10.

Yes. To sort numbers into order compare the same place value column digits from the left hand end; if the digits are the same, move to the next digit to the right - if any digit is missing it can be taken to be zero. The first digit of each is a units digit which are both 0, so compare the next digit (the tenths digit), which are also 0, so compare the next digit (the hundredths digit) which are also both 0, so compare the next digit (the thousandths) digit; now there is a 1 and a 2 with 2 > 1 → 0.002 > 0.001.

Six: 0, 1, 4, 5, 6 and 9

0 is a digit

Complementary angles are those that add up to 90. Therefore, the complementary angle of 90 is 0.

To round a number to a power of 10, you look at the digit in the place value column following the digit to which you wish to round; if it is 0-4 the number rounds down otherwise it rounds up. To round to the nearest 10, you look at the units digit; to the neatest 100, you look at the 10s digit, to the nearest 10,000 you look at the 1,000s digit. In every case the digit is a 9, so the number rounds up (each time) to 1,000,000.

20 = 2 × 10 → The last digit MUST be a 0 → The preceding digit must be even, ie one of {0, 2, 4, 6, 8}.

1 is a single digit, 0 is the absence of a digit.

Without repetition, 300. Of these 48 will have a 2 in the units place.