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88
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∙ 15y ago
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Is 88 a multiple of 4?
yes it is. 4x22=88.
What two simpler problems can you use to find 4x22?
Two simpler problems? It's not clear what this means.Maybe 2x44 or 8x11? - but they're not really simpler.Maybe (2x2)(2x11), but that doesn't get you closer to the answer.Maybe 4x20=80, 4x2=8 and 80+8=88 - but that's 3 simpler problems.If this is not your question, please clarify and ask the question again. :-)
12 plus 7 equals 4x-3?
12 + 7 = 4x - 312 + 7 + 3 = 4x22 = 4x22/4 = xx = 5.5
Is 88 a multiple of 4?
yes it is. 4x22=88.
Factor pairs of 108?
1x108 2x54 3x36 4x22 6x18 9x12
What is the quadratic equation of 4x22 7x?
Without an equality sign it can't be an equation but some kind of algebraic expression
What are the LCM of 4 8 and 88?
88 b/c 4x22=88 8x11=88 and88x1=88
What 2 simpler problems can you use to find 4x22 think about tens and ones?
-- You can use (4 x 20) and (4 x 2) . -- Please don't tell me what to think.
What two simpler problems can you use to find 4x22?
Two simpler problems? It's not clear what this means.Maybe 2x44 or 8x11? - but they're not really simpler.Maybe (2x2)(2x11), but that doesn't get you closer to the answer.Maybe 4x20=80, 4x2=8 and 80+8=88 - but that's 3 simpler problems.If this is not your question, please clarify and ask the question again. :-)
The average temperature for four days was 22 degrees What must the temperature be on the fifth day in order to make 23 degrees the average temperature for the five days?
For the 4 days the calculation must have been equivalent to 4x22/4 = 88/4. Next you want it to be 5x23/5 or 115/5. So the 5th temperature must be 115-88 which is 27. Like giving each 1 of the 5 days an extra degree.
How do you show your work for the greatest common factor of 18 and 30?
You can not find the greatest common factor for just one number. Ill will choose another number to compare 33 with. Lets choose 88.First take 33 and find all the numbers it divides into by a whole number33/3 = 11 So 3 and 1133/33 = 1 So 1 and 33the only factors are 3 and 11 ... 3x11=33and 1 and 33 ... 1x33=33it is written like this...33 - 1,3,11,33Now take 88 and find all the numbers that it divides into by a whole number88/2 = 44 So 2 and 4488/4 = 22 So 4 and 2288/8 = 11 So 8 and 1188/88 = 1 So 1 and 88So the factors of 88 are ... 2x44=88 ; 4x22=88 ; 8x11=88 ; 1x88=88it is written like this88 - 1, 2, 4, 8, 11, 22, 44, 88Now take all of the factors of 33 and 88 and find the number that is in common and that is the greatest. Did you find it...the answer is 11
