1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, 525
525 is divisible by 5 (in addition to 1 and itself). It is a composite number.
525 + (30%) = 682.5
The HCF of 525 and 231 is 21
tl
In its simplest form 525/1000 = 21/40
525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
All multiples of 525 (which are infinite) including 525, 1050, 1575, 2100, 2625 . . .
Yes, evenly
525 = 35 x 15
Yes.
Yes, the result is 175.
First determine which of the numbers are divisible by 5.They are:70430525Then you find the sum of these. 70+430=500. 500+525=1025.
The multiples of 105 (which are infinite) are all divisible by 105, including these: 105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
510
525 is divisible by 5 (in addition to 1 and itself). It is a composite number.
Find the sum of the first hundred even natural number divisible by 5?